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本帖最后由 fenghaili 于 2016-10-20 20:40 编辑 ( h* J6 o2 w6 b- E! l1 I( z
5 E( a [5 Q5 p, c7 d# u9 {比如：灰色框是板框，红色环形区域要开阻焊，结构给了开阻焊区域的外框和内框，我把结构图外框 直接zcopy成solermask层的shape，结构图内框 如何zcopy成这个shape的void？以实现环形开阻焊？ r+ g. v) Z- h5 {" j
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找到了一个办法。自己看吧！; Y# y: o4 Y$ ^- m7 t8 y: @6 P& y |# d
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" Y3 Q- n j/ [ T+ [: xCreate a void from a shape in AllegroStarted by spbae on 16 Nov 2010 9:21 AM. Topic has 1 replies and 10296 views. + r1 g6 {' n8 A' c/ N* \
Last post on 16 Nov 2010 4:09 PM by redwire.
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Hi all,
0 J1 k! K1 G4 H6 ~) ]& iI am trying to create a ring of exposed copper at the edge of a board by creating a shape on the solder mask top, however I can't seem to make an actual ring rather than a big filled plane. I can use z-copy to get the outer edge from my route keepin, but I can't figure out how to use a shape to generate a void (I would love to use z-copy to make the void the same shape as the route keepin, but contracted by 30 mils). Any suggestions, or is there something really obvious that I'm missing here?& t2 a. c4 A: k- H5 G
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I found a way to do this. If you create two unfilled shapes that represent the inner and outer boundaries of the ring (I did this by z-copying the keepin referenced above, once the same and once contracted by 30 mils, and decomposing both resulting line/arc items) compose a shape using these, it creates the ring exactly as I wanted it. I was going to delete this post, but I figured anyone looking for this might want my solution...
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发表于 2016-10-14 21:24
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