|
|
EDA365欢迎您！
您需要 登录 才可以下载或查看，没有帐号？注册
x
本帖最后由 fenghaili 于 2016-10-20 20:40 编辑 / J& O! c. H) j, o
$ C/ q; i4 I% m* E比如：灰色框是板框，红色环形区域要开阻焊，结构给了开阻焊区域的外框和内框，我把结构图外框 直接zcopy成solermask层的shape，结构图内框 如何zcopy成这个shape的void？以实现环形开阻焊？
4 Q5 S3 ?* C" o; G
( B" y$ ]# }' ?: n- f
& n6 I' A! [6 C找到了一个办法。自己看吧！
8 n4 Q; B* b% _ ^
1 U+ ]7 M" ^9 J
* w/ u, Z" z$ ^Create a void from a shape in AllegroStarted by spbae on 16 Nov 2010 9:21 AM. Topic has 1 replies and 10296 views.
0 Y1 E) u- ~8 K) n3 c; R3 a7 oLast post on 16 Nov 2010 4:09 PM by redwire.
- X4 Y7 j. p3 R8 x
7 }# v7 {- G _& ^% v0 {3 i' W$ t 9 B- C8 k3 x) V
) M1 @ V, j3 |( y8 w
9 H+ X9 U! D# Y9 ~
. v% W2 Q4 a4 G1 y% A
0 r7 m) R$ U% {4 `! P4 s2 ~
6 M: J' Q; s6 Y0 J4 B# |$ ~6 N' ~' U d
9 l5 T5 x! P2 p
; U8 s2 n9 g# s
Hi all,
: W6 M R& M. n' y- dI am trying to create a ring of exposed copper at the edge of a board by creating a shape on the solder mask top, however I can't seem to make an actual ring rather than a big filled plane. I can use z-copy to get the outer edge from my route keepin, but I can't figure out how to use a shape to generate a void (I would love to use z-copy to make the void the same shape as the route keepin, but contracted by 30 mils). Any suggestions, or is there something really obvious that I'm missing here? p9 ~- A2 ?, i4 T1 e5 p6 ~
Thanks! sp
2 M C3 d$ D, X) P1 }. T6 k
7 q, A( Y2 d; ?) n$ C" A[edit]/ M" M( [6 q5 W. d+ E
I found a way to do this. If you create two unfilled shapes that represent the inner and outer boundaries of the ring (I did this by z-copying the keepin referenced above, once the same and once contracted by 30 mils, and decomposing both resulting line/arc items) compose a shape using these, it creates the ring exactly as I wanted it. I was going to delete this post, but I figured anyone looking for this might want my solution...! ~$ _7 `. s0 K9 B1 `2 d
: @/ P# Q8 S; o( `% C5 H4 M( M, b+ T& l$ h- F4 @
|
|
/1 
发表于 2016-10-14 21:24
QQ好友和群
QQ空间
腾讯微博
腾讯朋友
微信
收藏
支持！
反对！
楼主
