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本帖最后由 fenghaili 于 2016-10-20 20:40 编辑
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4 N: p% \2 e+ x: {( `" ?7 W( v比如：灰色框是板框，红色环形区域要开阻焊，结构给了开阻焊区域的外框和内框，我把结构图外框 直接zcopy成solermask层的shape，结构图内框 如何zcopy成这个shape的void？以实现环形开阻焊？
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9 Y8 E# ~* T1 m" M$ J6 W" t找到了一个办法。自己看吧！2 O$ f) y( m2 O4 p3 F
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Create a void from a shape in AllegroStarted by spbae on 16 Nov 2010 9:21 AM. Topic has 1 replies and 10296 views. 9 I ~/ M& G( d3 E" l" d
Last post on 16 Nov 2010 4:09 PM by redwire.
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9 f' q% H3 Y3 g/ S' x; \Hi all,' F& ~+ ], ]0 L% k/ V
I am trying to create a ring of exposed copper at the edge of a board by creating a shape on the solder mask top, however I can't seem to make an actual ring rather than a big filled plane. I can use z-copy to get the outer edge from my route keepin, but I can't figure out how to use a shape to generate a void (I would love to use z-copy to make the void the same shape as the route keepin, but contracted by 30 mils). Any suggestions, or is there something really obvious that I'm missing here?3 r1 q/ }5 G P0 ?. L5 N- K! H0 F
Thanks! sp
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/ A0 C7 Z) s# pI found a way to do this. If you create two unfilled shapes that represent the inner and outer boundaries of the ring (I did this by z-copying the keepin referenced above, once the same and once contracted by 30 mils, and decomposing both resulting line/arc items) compose a shape using these, it creates the ring exactly as I wanted it. I was going to delete this post, but I figured anyone looking for this might want my solution...2 x. w6 L; @- y7 j
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发表于 2016-10-14 21:24
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