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这段文字如何理解呢?为何会进入亚稳态?

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发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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这段文字如何理解呢?为何会进入亚稳态?
9 g* Q0 [5 W  c: I8 l. T
- s% G$ d( Q+ X. o2 t3 z1 [" {If the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
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 楼主| 发表于 2007-12-18 21:50 | 只看该作者
The biggest problem with asynchronous resets is that they are asynchronous, both at the
( X4 O9 R) f3 \/ nassertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the
& J( a& O$ ^% X: m& d2 C) fissue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the' ~& f. t% o: R) c
output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
% U' d) w# O, @8 k* L  sAnother problem that an asynchronous reset can have, depending on its source, is spurious resets
- c% b: G; k# Gdue to noise or glitches on the board or system reset. See section 8.0 for a possible solution to
4 B# m/ B7 n0 G. l% Q6 N5 Qreset glitches. If this is a real problem in a system, then one might think that using synchronous
: p3 j/ M% B3 i3 v$ mresets is the solution. A different but similar problem exists for synchronous resets if these4 o, Q0 b* q/ {' O. z/ I* `
spurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is) P" X. E1 d  \$ ^9 T; T6 T
true of any data input that violates setup requirements).
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