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这段文字如何理解呢?为何会进入亚稳态?

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发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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这段文字如何理解呢?为何会进入亚稳态?+ q: J' r9 k, l9 a
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If the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
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 楼主| 发表于 2007-12-18 21:50 | 只看该作者
The biggest problem with asynchronous resets is that they are asynchronous, both at the) U% H! D3 m2 {4 q6 ~2 @3 {# G* D
assertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the0 v5 h0 O8 {" R  L
issue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the
1 d2 }3 l" J- @( Noutput of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.3 W: g  ]& g4 t, v4 h0 W
Another problem that an asynchronous reset can have, depending on its source, is spurious resets! a) F/ n- k2 m
due to noise or glitches on the board or system reset. See section 8.0 for a possible solution to9 c! H; I* T9 v( _; G
reset glitches. If this is a real problem in a system, then one might think that using synchronous
9 B6 F7 s6 S) F' W- f; uresets is the solution. A different but similar problem exists for synchronous resets if these
# k! i% k+ M* l. p1 y9 uspurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is( N3 K( h) i4 S! A$ D4 b
true of any data input that violates setup requirements).
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