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这段文字如何理解呢?为何会进入亚稳态?

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发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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这段文字如何理解呢?为何会进入亚稳态?3 q  M5 Z$ O( E( y

, F  N+ ~- |4 C( F8 T$ kIf the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
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 楼主| 发表于 2007-12-18 21:50 | 只看该作者
The biggest problem with asynchronous resets is that they are asynchronous, both at the
, h# p: g. Q) J1 r: Kassertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the, p$ [  N$ Y& Q0 l" A: r# _
issue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the
  X/ J# O* K" Y4 c7 ?/ Z3 ]output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
8 m# h4 _& ^: n$ B( T; s1 f) k7 rAnother problem that an asynchronous reset can have, depending on its source, is spurious resets% I/ [- \6 h9 ?5 G, h
due to noise or glitches on the board or system reset. See section 8.0 for a possible solution to
4 S  Z" q, i/ f4 _. b$ _$ preset glitches. If this is a real problem in a system, then one might think that using synchronous2 A5 o6 e9 K+ _: s+ W
resets is the solution. A different but similar problem exists for synchronous resets if these
; ~0 \! ?4 T, {( _1 `, K( T  cspurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is
: C( n' Y9 W: z, |true of any data input that violates setup requirements).
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