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Trace Width Calculator
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User Inputs:
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3 e8 {" u+ E7 l, yCurrent: I 1 [Amps]
' p! h c: ]4 B3 `3 W% XTemperature Rise: ▲T 10 [Degrees C]
h; a! N1 M' |/ K6 \+ NConductor Thickness: t 1 [oz. per sq. ft.] " w' u8 U( L# ^( H- @5 H, o' V
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Results:
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a$ k. a8 `: R+ ^7 |. j# `( [Internal Layer Results:
5 G* ]0 l+ Z& A& pRequired Trace Width: Wi 39.86495008 [Mils]
4 x+ s: N/ H2 c0 D2 f* P/ aCopper Area: 54.93390121 [Square Mils]
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/ b. _" ^" P" V. @External Layer Results: 9 A7 ?( Z8 n+ ~3 ~, x9 |) i
Required Trace Width: We 9.798650996 [Mils]
; t/ Z3 C, K( u U8 jCopper Area: 13.50254107 [Square Mils]$ e' p& E" Q% A& M; @8 h5 I! p
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# D; {' c+ A# j5 b: X) F! m3 hNOTE:
( K- C7 M( w& C+ {* Z& YThese Formulas are approximations!$ b0 |) V) v8 x s3 ?4 |+ L
They should not be used when a high degree of accuracy is required.
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