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本帖最后由 hi_yjs 于 2013-1-25 21:14 编辑
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最近用热敏电阻做个温度计。6 q1 @% B. l/ V
大家都知道,热敏电阻阻值随温度是非线性变化的,而且规格书也只是跳跃地给出部分对应值。
: I' v& f: b2 u4 X9 S请问该如何写出较高精度的程序呢?
$ m+ G2 E" M( O4 ^8 \! O(查表吗?那样表格会很庞大吧?而且取值也不好计算吧?)
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付热敏电阻部分对应阻值表:! |# Z3 c; \! c& |8 Y8 \& S
LT804;BValue25/50=4020;R25=100K
6 I \9 g- g7 l N温度 电阻值
: q: x& H2 K$ y% \2 z-50 7291.38
" p0 z& o2 c9 }6 K* D0 d* `* e-49 6774.88
' _8 a9 o% c" w8 r2 ~-48 6298.61; d9 L0 I+ k4 b9 G; `! v
-47 5859.17! ~8 U2 |% M/ w, e' v
-46 5453.45
/ D, h+ p O. h i) m/ y-45 5078.66& A6 W2 H9 z6 C' K! `4 v% b
-44 4732.225 t0 C. X" ^# T4 Q' u/ D K# a, k
-43 4411.8# G6 v M1 Y' P# |
-42 4115.28
8 v! U }0 J5 Q-41 3840.722 i+ @/ @6 S( k2 G8 X
-40 3586.35& J! F" G5 J+ _) F
-39 3350.55
9 Q8 \$ G. L- _* G5 L-38 3131.85& _8 ]! o5 S! v0 q
-37 2928.9
y6 F" Z# }" Z-36 2740.46' ]4 L8 J: {% L+ ^, L
-35 2565.40 Y4 Y2 ~, ^4 u3 U" X, K
-34 2402.691 J& O- X. }; J* ?
-33 2251.37
2 b p& s, O8 y' ~/ ^-32 2110.58
4 m2 m7 V1 H' r" z. C. w8 j+ d0 s-31 1979.52
- @6 V" }/ m- q2 E5 T3 _. |, j( c-30 1857.46
0 H, R$ u0 Z" w# h! A! c-29 1743.727 k" R$ d' X+ \. V8 h: _
-28 1637.68/ w9 s7 L- Y2 f+ y6 |5 G
-27 1538.771 c1 o% t5 m" l3 Y9 [9 n
-26 1446.476 y! l. `9 B2 D8 b8 s$ @
-25 1360.3: C, v" `/ f) U: c
-24 1279.82. j& Q% Q+ e" i5 F+ ?
-23 1204.614 P4 c0 P7 Q& l7 p$ v- A
-22 1134.29
% c5 S2 L* S9 n-21 1068.521 P+ a y9 ?2 S8 W6 N) p
-20 1006.98
8 C( g6 y7 |1 w' _5 z$ N0 ]0 \-19 949.368
7 Y1 g3 l' n! \9 ]-18 895.411
) L8 A. n s s, S* q O-17 844.8569 f- {6 H8 T5 X- N0 R: L0 l
-16 797.467* c$ V* W: U' ]- m* T
-15 753.028: P" x" j' A7 ]5 S/ q* _: K
-14 711.338# k+ D/ A; J3 X" u7 u( Z' g
-13 672.211
; J6 A }. q) v+ F# S-12 635.474
% z7 n1 l) N) ?# m6 f8 j-11 600.9673 P7 Z. u% Z i" R
-10 568.543
) G! \3 A% s% r4 G9 n+ f6 `9 G- r-9 538.063+ @" g: \7 i8 J4 p! n
-8 509.4
% r! _: k5 m G-7 482.435. h+ U- C! {9 L, l; K7 Z
-6 457.057
: M0 |8 B2 D8 @+ v3 n1 T3 o" Q-5 433.165+ h. ~0 U) x' H0 W4 S
-4 410.663- U) s. {- y/ d3 |1 |
-3 389.4625 D: ?+ F+ N/ y/ ^) ?* ^
-2 369.479) b; Z7 V% N7 L+ G! C3 y
-1 350.639
" B7 Y# f8 s; g* {. A, ^* b, n* i0 332.868) \3 w+ _& _& D6 {9 E/ c
1 316.102
- U* K% m E4 ^2 300.2765 O" G0 x9 b9 `+ E+ ]( }
3 285.334
, t2 \" q/ s9 s* m3 g4 271.221
- P8 ]+ n& A- T5 X1 j* F: B5 257.886
1 g2 R& s/ o2 j- v6 245.283; U- w. G* J8 K9 G5 C
7 233.367
. m) T# E6 V" X% k( ]# U2 u% o8 222.098
8 b$ x7 D, E( J; w3 L" V9 211.435
+ R# F- r: G) A4 m* F10 201.345$ w; `( N( X1 `2 J+ d
11 191.792) O# h0 }3 t6 N r
12 182.746& a0 Y+ Z" I* E, }& ~9 n6 `6 L5 Y
13 174.176
# ^3 ?# `7 [/ t3 A$ z+ r0 d14 166.056 e/ k8 M3 E7 c. ?* e F# X
15 158.359
* [5 N, u8 g- O" d3 i/ R16 151.06/ p! b2 L6 d4 X' E( {
17 144.138, B; X6 ~# Q; z) P( ^* h
18 137.571
! a) N3 R$ x. V19 131.339
& w) \) h' M2 Z- X20 125.423
. D6 I M. R( k( Z: k21 119.805
1 D& p$ z$ u/ G/ X22 114.469
3 N6 q) l" a8 Q/ d3 Z23 109.399. m6 O5 R: l; d! i/ e, \
24 104.581
7 o, A9 W. d* d t. i25 100
% _8 ?0 N5 n; N0 c& }3 {+ u* A26 95.6443
9 \5 F; B9 @4 p; O2 p27 91.5013
% A* C( A+ M/ n, ?% h8 I7 Q28 87.5596 t6 I; U& K0 o( p _! x
29 83.8083
. d; s7 g( `5 G30 80.2372
+ o! x3 X% o, G31 76.837& w; }$ b; p/ S
32 73.59848 i& _7 D9 R0 t7 X4 i% H- f
33 70.5131! o! d: ?, n9 G7 C- K
34 67.573, G% I% j8 ^6 p5 K g1 c7 x
35 64.7706% V: i6 a8 n9 g3 ~" B) z
36 62.0987
& X, F- n2 U" \) I& F37 59.5507/ c, T7 h4 ~) ]0 Z$ J0 `! F/ M
38 57.12024 `- @6 D' A1 x7 V7 k
39 54.8011
/ r) o8 a1 z# t z- V4 @0 i6 s40 52.588
8 u+ i3 w' h9 K) c41 50.4753$ }8 c8 R' d+ `) M
42 48.4581
3 R0 v' j# a) V1 u- V4 x- P. K43 46.53165 E2 n" W2 Z3 L8 b& Z; i
44 44.6913, g8 w1 |4 U9 S1 H* A' j1 A
45 42.933) m! D! D6 Q/ V8 e4 W: I
46 41.2525
1 m' c5 _3 o5 E# \+ ` ^: }+ S47 47.3965* R! R# x# Q' v5 H
48 38.11
1 _3 }+ Q/ ~' y6 Z) U49 36.6411# X" Z' O( x' u8 G* A0 P- G' j( N
50 35.236
+ D; Q( B$ c- n' l: j, c51 33.8916
+ P0 `- L5 ]- z9 M52 32.605 @9 V7 _: h6 K' y# {
53 31.3734/ m3 L2 D* B+ a: f: D9 X
54 30.1944+ U: w* x1 j, w1 ]$ ^
55 29.0653; |" H1 ]5 R$ j7 J) [) r
56 27.9839. _& `' k' P/ R8 I& N
57 26.9478
: l! Q! [9 m% F9 ?58 25.9551- S4 O* r" |7 w: b0 o' ~( i
59 25.0036
& A7 D2 b+ v% {& O0 v7 g60 24.0915
~/ W3 R) l4 w) K5 h+ G/ e0 u# `5 _0 ?61 23.217, v) V+ z! x, [% h0 B" R7 N
62 22.37845 M" B% `! G ]- A; W/ v
63 21.574
) w- U+ A1 ]$ u! U. c3 ~+ X( C64 20.80223 l- _2 \ ]1 c( Z# `2 H: R
65 20.0617
( C6 g+ E7 S4 h6 }+ e0 h66 19.3513 ?/ I. B; _, S u0 x: j9 C
67 18.6687
5 p1 D* e( W/ ?+ }; F0 G& V68 18.0137
) V. a& Y) d% s) z$ T- N- N( E69 17.3847/ y* e" f6 \0 z- e q' _1 x
70 16.7805. ]/ Z, B, e. n
71 16.2001! t. r+ u( X; H( z
72 15.6424$ i5 w* X& a' D$ V$ l* t
73 15.1064
# [& I! [" |" ?% D$ q74 14.5913
8 p' Y0 E' E1 U: ]7 v1 y7 Q( \75 14.096
4 e) T* F' k6 o' d2 Y# g76 13.6198
* _! q! i7 v9 v4 p- e77 13.1618" Q8 L3 I0 e4 t' g
78 12.72136 Y* j! |2 W! @, T! b
79 12.2975
- r) Z( ~4 O, p- C2 Q8 n8 S. x80 11.8897( x5 b0 {- o. `# U0 ?
81 11.49727 O! y# E7 D/ F- x
82 11.1195
- m3 q9 Q& \! j$ d3 A83 10.7558
9 p$ X. e( C; a' D9 u2 M2 o' W84 10.4056& t4 a6 H& h3 s8 F l, t
85 10.0684
5 J) b9 L+ u T& V86 9.7435) L4 m) e- b/ d; }1 [, n" r$ E
87 9.4306
: P4 v: }1 |, m7 Q88 9.1291$ O. V. J. {) c: R! ^1 Q
89 8.8385; W: Q4 j% F# j p# E
90 8.5585- F( g! W% K Z+ W
91 8.2885; t+ g- V* [ \7 L
92 8.0283
: D4 r3 m% g% l! a5 K93 7.7773. d; X5 \+ g! g+ X6 ]7 p
94 7.5352
4 h4 J" Y- J4 [95 7.3017
" d! F8 K5 J+ z* T( h96 7.07642 r/ Z1 m/ }8 ]
97 6.8591
( N5 i5 L# h. x9 `( X* V" \98 6.6493
& S# g: \0 L; N5 g4 q! M9 O2 g99 6.4469+ k$ `/ J7 K) i, l8 E
100 6.25157 [1 G' L4 ~; [( h `* n1 y1 d
101 6.06289 q. q( z+ m- r; o! v* m$ h
102 5.8806
( X0 `4 r$ s1 z1 \+ w103 5.7046) \4 g* g; Z4 s% }! o
104 5.5347
2 m' R" J8 s$ f! F105 5.3705
% A9 V# J0 K% L! q5 [" n9 x106 5.21195 M2 d8 C2 y1 Q& q$ q5 s' @
107 5.0586: E T2 Z" q6 W6 v
108 4.91046 H: N7 Z1 s: ^$ K& }+ D7 }
109 4.7672$ ]0 {5 b/ L( G1 K3 P: S2 M" H; R
110 4.6288- @1 [3 }: e8 b# ?. m; N
111 4.495& w n+ T% w3 I% c: \8 O; c, e
112 4.3655
( y9 W) y, L+ U5 _+ W0 Y" z113 4.2404" @$ C% F+ q- n3 m0 e6 b$ {
114 4.1193
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