|
EDA365欢迎您!
您需要 登录 才可以下载或查看,没有帐号?注册
x
大家好
8 [$ V, M% [2 g" {% n* J 小弟现在想做param参数扫描分析 但老是出错 有谁有相关资料的呀 共享一下了 谢谢了
$ H1 a& [0 e# `9 J( b( L( r0 t5 A/ {2 ?7 }7 z
我出错的内容是**** 05/15/08 09:39:24 ************** PSpice Lite (Mar 2000) *****************
& n! p6 q5 b" j6 S ** Profile: "Example-TRAN" [ G:\pspice\PSpice\Capture_Samples\anasim\example\example-example-tran.sim ]
' A& j- a ^$ W. K, R
7 \% u0 d( i3 r **** CIRCUIT DESCRIPTION- Q2 g5 s0 c6 T$ P: E: ~$ X
" t% `6 I1 p0 \4 x& t" A******************************************************************************1 }; k3 r- A- G3 e
- ?8 q6 h, W3 O
7 E9 X& T( e8 i( v** Creating circuit file "example-example-tran.sim.cir" 1 V% M" W. h( E. x( r0 f7 f
** WARNING: THIS AUTOMATICALLY GENERATED FILE MAY BE OVERWRITTEN BY SUBSEQUENT SIMULATIONS {, K. q- z0 J l/ f
*Libraries:
! j/ X9 ^ \+ f6 Q0 f/ j* Local Libraries :
! P# l( e: q0 R! v.LIB ".\example.lib" # n" O9 \- _' L+ r# k0 _
* From [PSPICE NETLIST] section of g:\pspice\PSpice\PSpice.ini file:
% r" Y% r9 r' C/ ~/ S.lib "G:\pspice\Capture\Library\PSpice\breakout.lib" ; v0 D H# w: _2 |7 A+ \4 G- I
.lib "nom.lib"
( |" D7 ^8 i2 m*Analysis directives:
: X' S; R9 R1 z* k/ k.TRAN 20ns 300ns 0 4 a' E F J- p- {- A$ n
.FOUR 1MEG v([OUT2]) 5 f2 E6 |4 F4 c$ G# l2 G: [
.STEP LIN PARAM a11 10k 100k 10
6 j- `$ V- g; y7 ^3 p9 D4 \- Y.PROBE V(*) I(*) W(*) D(*) NOISE(*)
3 R% |/ G: I; S0 b3 j: [7 m! R' v7 i6 r.INC ".\example-Example.net" ! q4 A# o$ q7 F9 u3 P
0 {8 i# C8 t" w* |- h
**** INCLUDING example-Example.net ****, {1 k6 I S0 u# n5 b+ ~
* source EXAMPLE
5 S" G) [' |( N' R" H7 A0 E4 Q4 iR_RBIAS N00078 VDD 20k
/ D: a" {/ | a/ f; o: c# mR_RC1 OUT1 VDD 10k
6 ~+ d2 U- b# u2 L5 m" Q' }R_RC2 OUT2 VDD a11 4 H" H0 Y6 j& B- a. n7 \0 b$ k
-----------------------------$% `) f; Q. K' s! n1 }& y4 ~% H
ERROR -- Missing value! B# R3 ]! D! H, N8 I& c; y
R_RS2 0 N00112 1k 2 a& u7 _" q# i+ y
R_RS1 N00061 N00240 1k ; @; F0 g! y7 l: ]0 t2 h4 Q
Q_Q1 N00078 N00078 VEE Q2N22222 F$ j9 G: H$ H: U0 A2 i. X
Q_Q2 N00315 N00078 VEE Q2N22228 p* b' P- ~: ~! T
Q_Q3 OUT1 N00061 N00315 Q2N22225 h0 V+ Y6 H9 g8 K+ M0 ^: i
Q_Q4 OUT2 N00112 N00315 Q2N22229 D( C2 q4 y$ R8 Y4 J" b
V_V2 VDD 0 12V) b' ?' O& i) ~% I i
V_V3 VEE 0 -12V% {4 K& Q; \! K0 w) d. ?4 m4 b
C_C1 OUT1 OUT2 5p 7 f6 L1 G n' x, z: C# O
V_V5 N00240 0 ! r, P |$ W7 K: a3 ?2 {! @- w' D
+PULSE 3.3 0 0 1ns 1ns 30ns 100ns
# k. `" Z( ~3 ~/ t& T9 R**** RESUMING example-example-tran.sim.cir ****
; X& b# g& B, R' k1 R.END |
|