EDA365电子工程师网
标题:
请教版主,如下D码,如何编写CAM350的".arl"模板 (cr5000设计的)
[打印本页]
作者:
1#####
时间:
2013-3-1 16:15
标题:
请教版主,如下D码,如何编写CAM350的".arl"模板 (cr5000设计的)
# 0 - mm
9 J2 D; S5 D3 [& \9 ]" t; K
# 1 - inch
! ?- [. j, w+ |/ w1 `1 L# `
# 2 - mil
. ^' s3 Z5 B, p, v I, R2 [
# 3 - micron
9 a/ g8 o5 k- q4 E6 D* ~0 L6 J$ v
#
( o* U' ]; E" a. r
Unit : 0
8 X# X$ j2 S' R
! r5 R+ P6 l; r2 y' y* W5 z( p/ U+ Q9 Z
#
' r* m% R. e5 q q8 R% j
# Aperture Table
0 T0 m+ @ Q. d) z; K/ |
#
# e u/ A0 a V. N7 {( u. H
# "[Code]:[Type]/[Posi,Nega]:[Figure]:[Size Parameters]"
4 u8 p- r) r+ {( N V& o& r7 m
#
- A1 o# }6 v: k+ Z
# Code - Aperture Code
$ j1 x, A0 ^" v# ^7 T
# Type - 'F'(Flash),'S'(Stream),'P'(Polygon)
. Y. O0 _1 Y) r0 H# o& J
# Posi,Nega - 'P'(Posi),'N'(Nega)
. \" G- n1 c- c* F6 C
# Figure - 'CI'(Circle),'SQ'(Square),
( @6 F. c: C5 N! \+ L
# 'RE'(Rectangle),'DO'(Doughnut)
: E0 Y# Q/ l) J a2 q( Z- m& f T
# 'RT'(Round Thermal),'ST'(Square Thermal),
8 Z* E( q X1 p- S7 c+ T. D; t
# 'CU'(Custom Aperture)
, F3 W) T' v6 Q
# Size Parameter - Figure is 'CI' -> '0.1'
1 b! \$ Y. `# R, v4 @, R' J
# Circle Diameter (Radius x 2)
) U3 P. N# d2 t2 @% P
# Figure is 'SQ' -> '1.0'
" E! y, f/ p8 N9 s! A" d4 V
# Square Width
1 M. H5 b8 o1 f a) M9 L7 n& R) }
# Figure is 'RE' -> '2.0/1.0/30'
) ?/ l. M( U( o5 X
# Rectangle Width,Height and Angle
/ r$ R# A; Y& ]
# Figure is 'DO' -> '3.0/1.0'
) {9 e9 N) n! f8 b* m3 U" g
# Circle Diameter and Inner Diameter
7 K, G8 x& e+ N U% H% v$ g
# Figure is 'RT' -> '3.0/1.0/0.1/4/0'
: _0 v4 W, d9 j2 ^! a
# Circle Diameter,Inner Diameter,
. a+ W4 S* V; w
# Slit Width,Slit Count and Start Angle
3 E6 D- C# X. d! I4 o. x C
# Figure is 'ST' -> '3.0/1.0/0.1/4/0'
6 ]) z+ X7 k9 e; R/ e, ^5 B! V
# Square Width,Inner Square Width,
( T, E, h! S0 {* F C$ b1 }
# Slit Width,Slit Count and Start Angle
; u. d$ C6 ?% | K
# Figure is 'CU' -> 'XXX/0'
2 P/ E& S+ Z* l8 L
# Pad Name and Angle
( _. W9 \, @6 |0 h( j2 k) |. q
#
5 j5 _! L3 a' O8 u; s) Q
ApertureTable 1 {
! b1 G) p% V4 N+ k" ?* n
"D010:F/P:CI:0.08500"
7 `8 B" f& p0 Y' t" @
1 h( Z- B j4 [; B
"D193:F/P:CI:10.00000"
0 Q; y' ~" t( z0 k
"D201:F/P:SQ:0.10000"
% D0 ~& i6 \3 ]9 U
9 q- ?, p" P9 c/ ^
"D510:F/N:RT:1.00000/0.60000/0.30000/4/45"
, r* s: ~' s$ O
+ [% p" V6 V5 o) p- Y
"D560:F/N:RT:6.00000/5.20000/0.40000/4/45"
0 q1 ~0 p1 c9 {0 j7 ?- ~: l
}
作者:
weiwei850125
时间:
2013-3-27 19:06
看不懂
作者:
1#####
时间:
2013-4-24 10:31
已解决,谢谢大家支持
欢迎光临 EDA365电子工程师网 (https://bbs.elecnest.cn/)
Powered by Discuz! X3.2