SI反射仿真问题

twffwt

VIH overshoot: VIH,max = VDDQ + 1.2V for a pulse width ≤ 3ns, and the pulse width cannot
; A0 J; B' _7 _: u' Pbe greater than one-third of the cycle rate. VIL undershoot: VIL,min = –1.2V for a pulse
% ]7 b: g. L2 f8 @; }  W9 a+ R- jwidth ≤3ns, and the pulse width cannot be greater than one-third of the cycle rate.

2 q+ ^6 x3 Z  |0 \大家是如何理解这段话的，比如供电电压为3.3V，是不是只要过冲电压小于4.5V，下冲电压大于-1.2V就可以了，我不大理解for a pulse width ≤ 3ns, and the pulse width cannot be greater than one-third of the cycle rate ，这句话是说的啥意思呢？？？