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如果有了一个器件的Spice模型文件，如何才能知道它和符号管脚的对应关系呢？比如下面是在官网下载的TS393的Spice模型文件，文件前面写的是：
& _$ A) c2 O& V! \' X% H" }; S* TS393 spice macromodel
7 N! Z4 t' d8 }, Z* CONNECTIONS :% s6 w% z0 N* @8 S6 ~5 G5 G
* 1 NON-INVERTING INPUT8 B5 @6 a! ^3 }4 U% a
* 2 INVERTING INPUT7 I. A2 @( D o H. k2 J
* 3 POSITIVE POWER SUPPLY
5 ]. z w* s( q1 |* 4 NEGATIVE POWER SUPPLY
4 D. Q, N! }4 \, I/ Q* 5 OUTPUT6 H7 \/ U4 W) {) w
7 r& N2 O( z( w& T+ X但是后面的内容没有3、4、5脚，却是这样写的：; N8 Q& I8 c( X0 I; M
.SUBCKT TS393 2 1 44 55 331 @& e+ M$ L1 h3 R1 L7 X* }
8 }/ o$ m3 E, Q O( V
把这个模型导入仿真软件时，显示的管脚号也是2、1、 44、55、33，那么问题来了，这些管脚号和这个比较器的NON-INVERTING INPUT（同相端）、INVERTING INPUT（反相端）、POSITIVE POWER SUPPLY（电源正端）、NEGATIVE POWER SUPPLY（电源负端）、OUTPUT（输出端）是如何对应的呢？这里有什么规则吗？
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谢谢！8 J, `( A$ B8 p4 E* l) I( E
: V- F- ?* r5 h; S- x$ M
附TS393的spice模型：
* h& @0 D0 S$ D; o5 e7 y, X% Q: A$ h: d( y" U
* WARNING : please consider following remarks before usage
( I4 z# |" Y7 d( V. T$ e- u*$ |/ J; a8 W' h L
* 1) All models are a tradeoff between accuracy and complexity (ie. simulation % ]7 g6 m) j& p7 J* c9 ]
* time).4 X) u) `( J( G$ w) u
* 2) Macromodels are not a substitute to breadboarding, they rather confirm the
- _: R$ O; t9 g, O: n& \* validity of a design approach and help to select surrounding component values. }" |' K# m( h6 F8 a
*1 D$ e0 L: s2 V" R7 N2 ]% Z
* 3) A macromodel emulates the NOMINAL performance of a TYPICAL device within ( ]% Y9 ^' w4 c/ Y1 T- p+ {
* SPECIFIED OPERATING CONDITIONS (ie. temperature, supply voltage, etc.).; [2 Q. x6 b1 Z- ^0 A# I# K, Z$ J
* Thus the macromodel is often not as exhaustive as the datasheet, its goal; ?/ C7 @0 z& X9 K9 [, j
* is to illustrate the main parameters of the product.$ q/ h* r9 ? M1 }$ @' O
*
8 D9 w' f+ \- b5 R' [1 @* 4) Data issued from macromodels used outside of its specified conditions& U+ _" J2 i$ J: w6 J
* (Vcc, Temperature, etc) or even worse: outside of the device operating 6 u% a4 Z1 y0 y$ A
* conditions (Vcc, Vicm, etc) are not reliable in any way.# o3 U7 H2 O7 p/ o8 Y
*-----------------------------------------------------------------------------------------" n& Y5 ^8 ?; \2 v/ v
* TS393 spice macromodel
4 ]* ~3 ~! u; k: R5 d* CONNECTIONS :0 a! `+ R- s& x& X
* 1 NON-INVERTING INPUT
V Y$ I: v) ]1 T& X* 2 INVERTING INPUT
! I3 H; |1 @; n2 X* 3 POSITIVE POWER SUPPLY7 @5 d5 r w$ B$ O' X
* 4 NEGATIVE POWER SUPPLY/ Q: |+ r5 _, y# ^/ T( D
* 5 OUTPUT' _9 e4 x2 i* n8 _+ Q
*% H% c! D; s7 s% c. V. j
**********************************************************
$ Y% Q" v: e' l& \0 ]! f3 E/ A! T- [.SUBCKT TS393 2 1 44 55 33
! K7 l, m# L! J5 e" t: _/ OEVCCP 4 0 44 0 1.0. k }) h' B' b; J% w0 A+ x1 a
EVCCN 5 0 55 0 1.0
" P# W$ F8 h$ ?VREADIO 3 33 DC 07 R* p' E" [3 H$ R- f9 J& k
G_ICCSAT 44 55 VALUE= {7.5E-6 + 5.0E-7*V(44,55)}
2 X/ z5 Z3 @/ p3 T$ b+ HG_IOUT_SINKED 55 0 VALUE={IF (V(1)<V(2), 0, I(VreadIo))}, l# D' E5 O; }& {! B8 ]) n% a
.MODEL MDTH D IS=1E-11 KF=1.050321E-32 CJO=10F
# n4 r% O/ D% q! I R- J.MODEL DIDEAL D N=0.1 IS=1E-081 g) E# v( y3 _+ x, P$ A
* INPUT STAGE0 d: f# J P/ P- E# K/ v2 u9 m
CIP 2 5 1.000000E-12' f/ \" P. |& a* |
CIN 1 5 1.000000E-12% P- U, j# M& Q9 V8 B
EIP 10 0 2 0 16 G. h2 X" P5 G; a- k. e
EIN 16 0 1 0 1
# {& X0 B+ o0 `4 K7 w8 {RIP 10 11 6.500000E+01/ w2 a8 q- m& k$ ~7 z
RIN 15 16 6.500000E+01
9 r, D! R( j# D- VRIS 11 15 1.939046E+029 e1 l; z0 [4 g/ k
DIP 11 12 MDTH 400E-12
6 y6 Z z& L0 K" ~DIN 15 14 MDTH 400E-12& a, X7 f5 |6 I& c: ^! e& d. {
VOFP 12 13 DC 0.000000E+003 s) D) o8 n7 V! @, K- b
VOFN 13 14 DC 0
4 s ]0 X# w) q9 t9 P8 J7 nIPOL 13 0 100E-06
( W: U \) O" \( F! }8 f. PCPS 11 15 8.5E-090 O% X8 Y; u8 P) W
DINN 17 13 MDTH 400E-12
. u1 i7 I/ m" p5 `. Z; wVIN 17 5 0.000000e+00
6 V' L8 T1 {+ ~9 b% GDINR 15 18 MDTH 400E-12- F' P' U% R1 h9 I. N7 u
VIP 4 18 1.200000E+005 {3 [# [5 C, s
FCP 4 5 VOFP 0.00
# K3 \/ u2 @4 p. bFCN 5 4 VOFN 0.00
: ]6 ]% _& S. d7 H$ fFIBP 2 0 VOFN 2.000000E-08, m( r0 o% j+ Q; O: O
FIBN 0 1 VOFP 2.000000E-08
% B$ g2 \7 a# `( j, k* AMPLIFYING STAGE* g- \3 F% a8 i1 j1 W @+ h0 G) i
RG1 5 19 2.8E+05. U# j6 }6 ^4 R4 M! z1 i$ q
RG2 4 19 2.8E+05
5 e3 D6 l4 w4 S6 i0 ^DONM 21 19 MDTH 400E-12
6 Y. T/ H7 `# I2 D( D; NHONM 21 27 VOUT 3000
4 S( s+ m7 N m) r! B! d1 OVINM 5 27 135
: L! a& z) e" l6 R3 U( PDOP 19 25 MDTH 400E-12
9 V1 P2 F6 X3 H2 J& A, PVOP 4 25 1.097
3 a5 [ i) U4 _' ^DON 24 19 MDTH 400E-123 L) E% L- Z. r3 @# N
VON 24 5 1.097
0 s/ G# c* Q0 o/ yFIP 0 19 VOFP 104 0 y& b( j! C [7 J4 Z
FIN 0 19 VOFN 104* R r1 k, ]& u4 s! r6 {' f& M
EOUT 26 23 19 5 10 e9 |8 [. v8 {
VOUT 23 5 0V* i4 ~) m6 k$ A1 x) m% V7 ~5 Y9 b$ Q
RFUIT 126 5 2.5E+09) S- e6 d' r6 V+ n+ T3 x) f Y b
DOUT 126 26 DIDEAL 400E-12
0 s( U1 z4 `3 \- V# MROUT 126 3 28.33
8 L# F! n/ u3 V! ]( y.ENDS- _ B0 j7 F% n+ k% `) j, ~4 m( ^, Y
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发表于 2015-12-10 20:08
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楼主
。不知道你哪里有没有比较详细的Spice方面的资料？你说的那个我现在明白了：7 [2 P2 N# h! k3 K$ N
