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本帖最后由 fenghaili 于 2016-10-20 20:40 编辑 $ U. E2 n' `# c. \, Y. |
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比如：灰色框是板框，红色环形区域要开阻焊，结构给了开阻焊区域的外框和内框，我把结构图外框 直接zcopy成solermask层的shape，结构图内框 如何zcopy成这个shape的void？以实现环形开阻焊？1 K0 o- }9 l1 s" d% Q) ?6 v( V! ^
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找到了一个办法。自己看吧！+ X7 r* ~* B- N; U$ k
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Create a void from a shape in AllegroStarted by spbae on 16 Nov 2010 9:21 AM. Topic has 1 replies and 10296 views. 7 P/ a$ [' q" u8 K5 v' Y
Last post on 16 Nov 2010 4:09 PM by redwire.5 V0 i# t% g$ y* ^: ~
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Hi all,+ y# ]: i0 P- k* D. ? j5 Z9 y
I am trying to create a ring of exposed copper at the edge of a board by creating a shape on the solder mask top, however I can't seem to make an actual ring rather than a big filled plane. I can use z-copy to get the outer edge from my route keepin, but I can't figure out how to use a shape to generate a void (I would love to use z-copy to make the void the same shape as the route keepin, but contracted by 30 mils). Any suggestions, or is there something really obvious that I'm missing here?
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I found a way to do this. If you create two unfilled shapes that represent the inner and outer boundaries of the ring (I did this by z-copying the keepin referenced above, once the same and once contracted by 30 mils, and decomposing both resulting line/arc items) compose a shape using these, it creates the ring exactly as I wanted it. I was going to delete this post, but I figured anyone looking for this might want my solution...
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发表于 2016-10-14 21:24
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