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9 m$ g. H' M- ~+ ]% c @ 小弟现在想做param参数扫描分析 但老是出错 有谁有相关资料的呀 共享一下了 谢谢了 7 a- t2 V! [* U" n# g4 d& F! t
$ b x9 l2 h4 f- R0 z3 \3 @1 L我出错的内容是**** 05/15/08 09:39:24 ************** PSpice Lite (Mar 2000) *****************' V! F1 P% w, q5 e1 N' S1 i# e' x
** Profile: "Example-TRAN" [ G:\pspice\PSpice\Capture_Samples\anasim\example\example-example-tran.sim ]
v6 l8 e r& J+ ]7 P; i
! H. w& B* k: p$ p **** CIRCUIT DESCRIPTION
$ {0 \/ Q% q, `4 ^! y/ J
0 w8 s9 T. s1 Z+ ?4 |! k4 X******************************************************************************
/ d1 `% x# g+ ]1 u! ?6 d2 s# i3 O& }8 G' {1 N1 a9 m. |* {+ u
' b9 l$ c- `1 u$ ?6 b2 i
** Creating circuit file "example-example-tran.sim.cir" 3 l) Z' R; E- a% o2 ]
** WARNING: THIS AUTOMATICALLY GENERATED FILE MAY BE OVERWRITTEN BY SUBSEQUENT SIMULATIONS
7 G8 C! x( H& |" F- ~& j T*Libraries: 2 X# C3 z6 a# K$ ~& @
* Local Libraries :
! p; ~& K' q8 j( s2 j" E% p4 n.LIB ".\example.lib" : N& v/ }# r8 F1 E! f. b$ u
* From [PSPICE NETLIST] section of g:\pspice\PSpice\PSpice.ini file:# y- ~0 h( i, W) w% W; J% M3 A. @
.lib "G:\pspice\Capture\Library\PSpice\breakout.lib" ; ]5 e' h& W+ o* x/ p# C
.lib "nom.lib"
, G$ f2 u" F& j! t. C1 W% g*Analysis directives:
, i( p/ K _: T7 {' T% V.TRAN 20ns 300ns 0 ; E* G& e& w+ z
.FOUR 1MEG v([OUT2]) / [5 u- y, S5 W7 A$ \% q4 }; T9 g
.STEP LIN PARAM a11 10k 100k 10 ; ^3 g* }( n# \" r
.PROBE V(*) I(*) W(*) D(*) NOISE(*)
" k5 _+ [7 N7 Q.INC ".\example-Example.net"
% | M, m8 g+ a$ \; ^$ C
# n" U4 r2 Q: { \" t**** INCLUDING example-Example.net ****
. B7 J8 B8 s! J* Q# H, f* source EXAMPLE0 Z+ w- r1 [8 o2 y9 K. u
R_RBIAS N00078 VDD 20k + j' w' a$ n* j; ]1 Q0 q ~
R_RC1 OUT1 VDD 10k . Y: m4 b. }6 q. L1 l
R_RC2 OUT2 VDD a11
1 t# c: n# w) H8 o0 T m-----------------------------$
+ M$ }: ?& g; u3 U9 l2 rERROR -- Missing value
! k% j1 e( w9 p5 W9 L; M2 y) WR_RS2 0 N00112 1k
6 L5 P5 ~6 S8 ?+ n0 pR_RS1 N00061 N00240 1k
: u3 f- r3 x4 |! r# OQ_Q1 N00078 N00078 VEE Q2N2222
& V- H o! g. K. U" o9 e( b2 LQ_Q2 N00315 N00078 VEE Q2N2222
- R( _- L. p" M$ \! x/ r; X7 aQ_Q3 OUT1 N00061 N00315 Q2N2222/ l0 R- k: K( L. f! F( U
Q_Q4 OUT2 N00112 N00315 Q2N2222
( I$ T; _0 ~1 \- c9 z7 ?6 F/ vV_V2 VDD 0 12V+ F2 m: x1 b. y1 {4 ?1 y& j
V_V3 VEE 0 -12V
) n! B9 Y- V; ~/ t! PC_C1 OUT1 OUT2 5p 4 f: _# ~/ A8 G2 C/ E8 Z' x
V_V5 N00240 0 - p) c6 v5 y2 `. V2 |& A# m8 D6 n& r9 U
+PULSE 3.3 0 0 1ns 1ns 30ns 100ns
4 M; d/ q" }0 v**** RESUMING example-example-tran.sim.cir ****
% L. b4 Q& l A: c' V& K.END |
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发表于 2008-5-15 09:59
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