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如果有了一个器件的Spice模型文件，如何才能知道它和符号管脚的对应关系呢？比如下面是在官网下载的TS393的Spice模型文件，文件前面写的是：
5 ]) [4 K0 o. l' q: R5 V* TS393 spice macromodel
) c8 W. F8 ^# `$ r0 o7 V* CONNECTIONS :$ e2 c& d4 C! i W$ {
* 1 NON-INVERTING INPUT9 k4 S: q4 [( U( \, a8 J, |
* 2 INVERTING INPUT
, T# B% ^; H! L* 3 POSITIVE POWER SUPPLY
& J$ r3 g: e* [7 C6 Z( h9 L9 W* 4 NEGATIVE POWER SUPPLY- I% n/ ^; p! G" {7 X: ?' Z
* 5 OUTPUT7 U2 j: J" V( b2 S3 c
H0 X, q% o7 `& s% z) J但是后面的内容没有3、4、5脚，却是这样写的：
+ x4 V d1 g( W.SUBCKT TS393 2 1 44 55 33% v9 g2 Y+ Y0 T
: e y V; m+ Z8 E把这个模型导入仿真软件时，显示的管脚号也是2、1、 44、55、33，那么问题来了，这些管脚号和这个比较器的NON-INVERTING INPUT（同相端）、INVERTING INPUT（反相端）、POSITIVE POWER SUPPLY（电源正端）、NEGATIVE POWER SUPPLY（电源负端）、OUTPUT（输出端）是如何对应的呢？这里有什么规则吗？
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8 t2 _9 _# J, T谢谢！6 O: ?! {* _) ]/ c7 D% K+ { Y
2 W; u9 G4 f+ X
附TS393的spice模型：
3 \4 E+ \( r5 t6 U7 R$ C$ ]
$ Y# i# K& _3 ?# p% o8 r x* WARNING : please consider following remarks before usage
& v4 j% i9 K* A) J3 [*4 D p6 y i2 x
* 1) All models are a tradeoff between accuracy and complexity (ie. simulation . C! U6 c8 y2 l j: O" W% K; {
* time).
% H; N7 T: e( Q2 e* 2) Macromodels are not a substitute to breadboarding, they rather confirm the `2 ?7 y7 J4 R- p) z1 F
* validity of a design approach and help to select surrounding component values. Q3 Y4 N+ p# |; M, X m- z
*
8 x3 R; P6 ~) R& ]' C% a0 g( U* 3) A macromodel emulates the NOMINAL performance of a TYPICAL device within 3 a* f8 F' U6 W' |
* SPECIFIED OPERATING CONDITIONS (ie. temperature, supply voltage, etc.).
: p- V+ w& r) L: i/ {* Thus the macromodel is often not as exhaustive as the datasheet, its goal; o: I% r9 R7 M- l
* is to illustrate the main parameters of the product.
2 z8 S3 r) o: X*' b/ f2 I9 z4 V+ a, G/ v' _
* 4) Data issued from macromodels used outside of its specified conditions" c9 J* |8 J+ T, ]# U# f- H( V T5 G
* (Vcc, Temperature, etc) or even worse: outside of the device operating 5 k8 q3 ~+ i0 _! R3 j- g: D7 f
* conditions (Vcc, Vicm, etc) are not reliable in any way.
* f" i( ]( ]! l' Q1 e4 }7 ^, }*-----------------------------------------------------------------------------------------0 S( B E6 K9 |) _% w
* TS393 spice macromodel4 Q0 |( d. `( j8 K' S
* CONNECTIONS :
6 e6 y1 E7 f6 P5 \* 1 NON-INVERTING INPUT+ J) s1 L* N9 Q4 I6 H
* 2 INVERTING INPUT
+ s# e* N) E; j, L1 N, Y* 3 POSITIVE POWER SUPPLY! B4 }( q* _: K7 j
* 4 NEGATIVE POWER SUPPLY4 {8 ~6 W' n* }3 u4 o5 ~: W+ A
* 5 OUTPUT' q( X5 D! x0 \/ T
*; y8 F! Q$ K" `2 y, c# R2 Z" s3 X) Y
**********************************************************
/ X% A8 E9 O7 A% B- t.SUBCKT TS393 2 1 44 55 330 M: L6 b0 L% C# G# q/ l8 X& w( T
EVCCP 4 0 44 0 1.05 ]& u- Y; u3 c9 {; M
EVCCN 5 0 55 0 1.0
# O3 [/ [7 u, P. Y5 v) ?+ l% B; o1 DVREADIO 3 33 DC 0
* K$ C( k+ T/ I# n) `G_ICCSAT 44 55 VALUE= {7.5E-6 + 5.0E-7*V(44,55)}
N5 s! ? r" |+ j ~' HG_IOUT_SINKED 55 0 VALUE={IF (V(1)<V(2), 0, I(VreadIo))} E, k- j8 b) S" C4 E
.MODEL MDTH D IS=1E-11 KF=1.050321E-32 CJO=10F7 R+ m8 `9 S7 a: v% U: Y: z) l
.MODEL DIDEAL D N=0.1 IS=1E-08 x2 q) q, X: }: V) ~ G
* INPUT STAGE0 D9 a0 |( F4 q% I( P, n- B# J) p A4 f
CIP 2 5 1.000000E-12
& ]/ K! y- [- WCIN 1 5 1.000000E-127 D$ d, F+ Y8 X9 _ S
EIP 10 0 2 0 1# `9 l% x' q. H3 j+ p$ B
EIN 16 0 1 0 1
. F5 l7 G* V0 J. YRIP 10 11 6.500000E+011 Q3 g" A9 o; |0 E" X
RIN 15 16 6.500000E+01# [ H0 ^. @# r: ^7 T
RIS 11 15 1.939046E+02
3 D, U( u* k& j# i1 q2 k! H0 `DIP 11 12 MDTH 400E-12" A4 q7 X8 P: ?6 A! n
DIN 15 14 MDTH 400E-12$ w& M9 L/ f G' }% b$ z
VOFP 12 13 DC 0.000000E+00
6 y( G9 W5 r, n8 d9 W' gVOFN 13 14 DC 0
3 a$ r7 D, f; x: ^% xIPOL 13 0 100E-06! z3 q' m4 J1 P+ ?* |" `% k
CPS 11 15 8.5E-09
7 B- t! {- T5 R! sDINN 17 13 MDTH 400E-12
+ S" \) i# W* R9 e3 CVIN 17 5 0.000000e+00% c l0 r1 F+ u) ?6 m& t2 C( _
DINR 15 18 MDTH 400E-12! R% j) h- y# L& e; r9 Z
VIP 4 18 1.200000E+00
s Y; q2 F2 l4 m4 y/ i: R9 U. ^3 sFCP 4 5 VOFP 0.00 / c1 I. N. G Y
FCN 5 4 VOFN 0.00
6 n# S4 f; p. J/ B" \ s) JFIBP 2 0 VOFN 2.000000E-08% i" {' s/ G. b' o$ G
FIBN 0 1 VOFP 2.000000E-082 E! E0 _0 @3 |7 V
* AMPLIFYING STAGE
8 Z7 @; H# `2 q( j. `RG1 5 19 2.8E+05: _9 H2 A, b" ?& _
RG2 4 19 2.8E+05
5 v% A# d$ W4 x6 i+ RDONM 21 19 MDTH 400E-125 i$ e, C% \* e+ ?% v7 f
HONM 21 27 VOUT 3000
: o8 Z$ g% }0 y+ }VINM 5 27 1356 ~& e, q' j" |! {
DOP 19 25 MDTH 400E-12
4 |" Q6 l8 [: D. yVOP 4 25 1.0973 R5 P: C; M" Y% V
DON 24 19 MDTH 400E-12
) u- s! R2 ?3 XVON 24 5 1.097# E+ f: k# P* i3 P+ R
FIP 0 19 VOFP 104 & Y# q; ^0 C& l% f
FIN 0 19 VOFN 104% i" _% I6 N# @8 G4 b4 L
EOUT 26 23 19 5 1, j) k; U$ Q l
VOUT 23 5 0V
2 g8 n; P9 a/ I% kRFUIT 126 5 2.5E+09# n$ b$ s* u$ Y: K( h- F
DOUT 126 26 DIDEAL 400E-12; D1 i0 B D5 d
ROUT 126 3 28.33$ J2 X: F6 K9 |
.ENDS* f1 P2 J% W8 P+ D/ {9 }! [
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发表于 2015-12-10 20:08
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楼主
。不知道你哪里有没有比较详细的Spice方面的资料？你说的那个我现在明白了：