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这段文字如何理解呢?为何会进入亚稳态?

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发表于 2007-12-18 21:19 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式

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这段文字如何理解呢?为何会进入亚稳态?1 M6 O( M, x" |! L. E: H8 p
  t' \* ^& k6 w' m, B5 O
If the asynchronous reset is released at or near the active clock edge of a flip-flop, the output of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
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 楼主| 发表于 2007-12-18 21:50 | 只看该作者
The biggest problem with asynchronous resets is that they are asynchronous, both at the9 k2 }& s  s% f1 H3 F* `
assertion and at the de-assertion of the reset. The assertion is a non issue, the de-assertion is the
, b$ G/ ]2 R8 r) j9 ~' iissue. If the asynchronous reset is released at or near the active clock edge of a flip-flop, the
* k. F8 u: G; {$ y% e. S0 uoutput of the flip-flop could go metastable and thus the reset state of the ASIC could be lost.
7 _# H  Q3 ~! }7 GAnother problem that an asynchronous reset can have, depending on its source, is spurious resets0 x' n/ T" ?3 [- {$ w0 L
due to noise or glitches on the board or system reset. See section 8.0 for a possible solution to
8 }# ^, r. I* j  ereset glitches. If this is a real problem in a system, then one might think that using synchronous
6 h) ?  N  f9 J9 H" |1 p( oresets is the solution. A different but similar problem exists for synchronous resets if these
9 B! w$ @5 H  N# X7 k6 |spurious reset pulses occur near a clock edge, the flip-flops can still go metastable (but this is
. w; m& Q+ c, C0 z. G8 ztrue of any data input that violates setup requirements).
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