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我从TI的官网上下了一个INA331的库,自己建好添加后,进行Pspice仿真。结果出错了,我看了很多教程,都没用。应该不是添加的问题,可能是破解的问题,因为TI的工程师都没能搞定。) k2 h* ]7 G' u; x
下面是错误信息。
4 l: e7 r# ?; d1 v4 T5 P**** 07/30/10 20:21:36 ******* PSpice 16.3.0 (June 2009) ****** ID# 0 ********
: J$ e9 J" W! }* ]; {( f& X** Profile: "SCHEMATIC1-ina331" [ F:\ina331\ina331-pspicefiles\schematic1\ina331.sim ] ( p# ^4 m" h- m- L( m! E6 ^
i6 R) L' h) M) b) b* \0 J
**** CIRCUIT DESCRIPTION: Z; e- L3 R3 ~3 o- J
8 ^8 c' j5 z2 J+ S# f. ^( b! ]6 M******************************************************************************2 G _. J" a1 ?6 m0 X, c5 p
( j' M7 z% Q3 Z- s, M6 }( b" ^
5 J' R# N Q: ?) c9 W8 ^/ N
** Creating circuit file "ina331.cir"
3 ?& x7 m$ \, {$ H) Q7 I+ }** WARNING: THIS AUTOMATICALLY GENERATED FILE MAY BE OVERWRITTEN BY SUBSEQUENT SIMULATIONS
g, {/ b" H$ F2 H1 h. K*Libraries: ) |% w. ~$ Q: a: ^
* Profile Libraries :
% H( [* v' _% w1 j4 r* Q' J* Local Libraries :
~& [ u( V( t! K* From [PSPICE NETLIST] section of F:\Cadence\SPB_16.3\tools\PSpice\PSpice.ini file:* y. M/ n' _* `7 S* J& m
.lib "F:\Cadence\SPB_16.3\tools\capture\library\Userlib\INA331.lib" " y; z7 B, M( L, K
*Analysis directives:
& I2 s; A& j' h+ U. Q9 \: e ^% h.TRAN 0 1000us 0 2n
/ d8 j, i. n1 H7 X2 Y% _, M.PROBE V(alias(*)) I(alias(*)) W(alias(*)) D(alias(*)) NOISE(alias(*)) & V; ^ ~# K" A. |
.INC "..\SCHEMATIC1.net"
3 z- D' `" c/ I6 \% n' N! \0 k0 h
) d( F5 \/ K3 E* H**** INCLUDING SCHEMATIC1.net ****" d2 O: y' s0 B! R7 M& `" [
* source INA331
2 C+ @, h$ ?1 K* [R_R1 0 N00576 40k
7 ?& d) `) V8 w3 xR_R2 N00576 N00608 40k
" u! g; G$ ~7 s6 Z% ?+ {R_R3 N00608 0 150k 8 q9 E) J6 r- }; Q, W4 y
C_C1 N00576 N00608 3p
L+ Z2 i1 ]2 n, ~# i1 AV_V1 N00453 0 5$ w1 E$ h- B( L! q _# W& C
V_V2 N00352 0 2.5* Y, t1 E! f; w, d% u# [' b
V_V3 N01435 0 4
$ m6 L" n+ E' T# l/ a/ RV_V4 N01420 0 1.25" ~7 G6 R+ g% O/ p# ]
V_V5 N00361 N00352 1 z+ K0 ^2 E/ b( D9 \& U& G
+SIN 50mv 0 100k 0 0 04 N9 s! X7 G; ~" Z" b
X_U1 N00576 N00361 N00352 0 N01435 N00453 N00608 N01420 INA331
+ R( `$ i+ S5 q* ~7 b! e# ^4 ~**** RESUMING ina331.cir ****0 o0 s* X9 A- f r K: h2 C5 ~
.END& ^1 K: f) k: R
$ f7 u% C1 d/ o0 D3 n$ U# U- R$ B**** EXPANSION OF SUBCIRCUIT X_U1 ****- H8 T8 Q3 u, e# ^
X_U1.C48 X_U1.192 0 280P, V8 i) M7 q- }! o6 B+ I; B
X_U1.R187 X_U1.88 X_U1.82 39997 TC1
( c2 O4 ?, Q, J--------------------------------$5 @4 s5 L& S- R3 N6 p
ERROR -- unknown parameter
' U+ H7 h5 s- y: |+ 800E-6( L; z: _" g. y% b& |
X_U1.R188 X_U1.23 X_U1.88 10E3 TC1
# h3 e$ I$ Z2 U6 h4 z-------------------------------$
% c: i1 j& r, V7 F6 r" ]$ ?ERROR -- unknown parameter0 l F. A$ w ]% `- L, V
+ 800E-6# v. J4 E# t2 |; Q
X_U1.R184 X_U1.29 X_U1.23 10E3 TC1+ [2 q q/ y' L# E/ j
-------------------------------$
% [- U1 T; t2 u. w s, w+ uERROR -- unknown parameter- u6 G7 R( U( }; j& n) ]8 W
+ 800E-6$ L( k2 Q+ z5 n- M2 l6 _
X_U1.R185 N01435 X_U1.29 40E3 TC1; D; r1 d4 H& u6 {1 G( _. L# M3 o
------------------------------$
( w& D' |, I, yERROR -- unknown parameter
: _7 R; K! A7 O/ I7 X1 `$ |& p希望有能解决这一难题的中国高手。 |
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