标题: SI反射仿真问题 [打印本页] 作者: twffwt 时间: 2012-10-26 18:49 标题: SI反射仿真问题 VIH overshoot: VIH,max = VDDQ + 1.2V for a pulse width ≤ 3ns, and the pulse width cannot4 Z8 L$ b& a# F) g# {! E) U- E
be greater than one-third of the cycle rate. VIL undershoot: VIL,min = –1.2V for a pulse ! N9 ]7 d) r% v. y3 E& c4 g1 kwidth ≤3ns, and the pulse width cannot be greater than one-third of the cycle rate.! U/ `/ ? q! l
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大家是如何理解这段话的，比如供电电压为3.3V，是不是只要过冲电压小于4.5V，下冲电压大于-1.2V就可以了，我不大理解for a pulse width ≤ 3ns, and the pulse width cannot be greater than one-third of the cycle rate ，这句话是说的啥意思呢？？？